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-n^2-1.2n=0
We add all the numbers together, and all the variables
-1n^2-1.2n=0
a = -1; b = -1.2; c = 0;
Δ = b2-4ac
Δ = -1.22-4·(-1)·0
Δ = 1.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.2)-\sqrt{1.44}}{2*-1}=\frac{1.2-\sqrt{1.44}}{-2} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.2)+\sqrt{1.44}}{2*-1}=\frac{1.2+\sqrt{1.44}}{-2} $
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